An ideal gas is sealed within a container at a tempreture of 17 degree celcies and a pressure of 101KPa. The container is heated until the tempreture of the gas reaches 100 degree celcies. A valve in the container is then opened to allow gas to escape until the pressure falls back to 101KPa at 100 degree celcies. 1) calculate the pressure in the gas just before the valve is opened. 2) calculate the fraction of the initial mass of gas that was lost as a result of opening the valve.

Question

An ideal gas is sealed within a container at a tempreture of 17 degree celcies and a  pressure of 101KPa. The container is heated until the tempreture of the gas reaches 100 degree celcies. A valve in the container is then opened to allow gas to escape until the pressure falls back to 101KPa at 100 degree celcies. 1) calculate the pressure in the gas just before the valve is opened. 2) calculate the fraction of the initial mass of gas that was lost as a result of opening the valve.

Mr. Unknown · Accepted Answer

(a) p1/t1 = p2/t2
p2=p1(t2/t1)
p2=100kpa(373/290)
p2=101x10^3 pa (1.286)
p2=101x1286
p2=129,886pa or p2=129.886kpa
or in simple way
p2=101x10^3(1.286)
p2=101x10^3(1286x10^-3)
p2=101x1286
p2=p2=129,886pa or p2=129.886kpa
(b)

Reed · Answer

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