Asked by tyger2020
What is the angular momentum of the Moon in its orbit around Earth in kg m2/s?
I do not have any information about the moon, so I looked it up, but I got the question wrong so I don't know what values I should be using...I got 5.7 * 10^35.
Thank you!
I do not have any information about the moon, so I looked it up, but I got the question wrong so I don't know what values I should be using...I got 5.7 * 10^35.
Thank you!
Answers
Answered by
bobpursley
you need the radius, and the period
Momentum=1/2 m r^2 2PI/periodinSeconds
you can look up mass moon, radius of orbit, and calculat the period in seconds (you know its orbit period is 28days).
Momentum=1/2 m r^2 2PI/periodinSeconds
you can look up mass moon, radius of orbit, and calculat the period in seconds (you know its orbit period is 28days).
Answered by
Scott
angular momentum of the moon is
... mass * velocity * orbital radius
orbital radius is earth-moon distance
... 385000 km ... (time averaged)
velocity (average) ... 1022 m/s
mass ... 7.342E22 kg
values courtesy of wikipedia
... mass * velocity * orbital radius
orbital radius is earth-moon distance
... 385000 km ... (time averaged)
velocity (average) ... 1022 m/s
mass ... 7.342E22 kg
values courtesy of wikipedia
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