Asked by kb
what is the angular momentum quantum number for the orbital from which an Mg atom loses two electrons to form Mg2+ ion.
Answers
Answered by
DrBob222
12Mg = 1s2 2s2 2p6 3s2
It loses the two 3s electrons. The angular momentum quantum number is l = 0 for the s orbital and that is in units of h/2*pi
It loses the two 3s electrons. The angular momentum quantum number is l = 0 for the s orbital and that is in units of h/2*pi
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