Question
What is the angular momentum of a 0.200- ball rotating on the end of a thin string in a circle of radius 1.45 at an angular speed of 13.0 ?
Answers
Angular momentum is L = I•ω,
where I = m•R² is the moment of inertia of the material point.
L = I•ω = m•R²• ω =
=0.2 (kg)•(1.45)² (m²) •13 (rad/s) =
=5.47 kg•m²/s.
where I = m•R² is the moment of inertia of the material point.
L = I•ω = m•R²• ω =
=0.2 (kg)•(1.45)² (m²) •13 (rad/s) =
=5.47 kg•m²/s.
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