Asked by Mike
Find dy/dx for y=3tan^-1(x/2).
I know the answer is 6/x^2+4 but I'm stuck at y'=3(1/1+(x/2)^2)(1/2)
I know the answer is 6/x^2+4 but I'm stuck at y'=3(1/1+(x/2)^2)(1/2)
Answers
Answered by
Steve
so far, so good ...
dy/dx = 3/(1+(x/2)^2) * 1/2
= 3/[2(1+x^2/4)]
= 3/[8(x^2+4)]
dy/dx = 3/(1+(x/2)^2) * 1/2
= 3/[2(1+x^2/4)]
= 3/[8(x^2+4)]
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