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Asked by Dylan

3tan (x- pi/5)-sqrt(3) =0
5 years ago

Answers

Answered by Reiny
3tan (x- pi/5)-sqrt(3) =0, I will assume you want 0 ≤ x ≤ 2π
3tan (x- pi/5) = √3
tan (x- pi/5) = √3/3
angle in standard position: tan Ø = √3/3, Ø = appr .5236 radi
but the tangent is also positive in III so Ø = π + .5236

case 1:
x - π/5 = .5236
x = 1.1519

case 2:
x - π/5 = π + .5236
x = 4.2935
5 years ago
Answered by oobleck
tan (x- π/5) = √3/3
so, x - π/5 = π/6 or 7π/6
x = 11π/30 or 41π/30
5 years ago

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