Asked by Anonymous
A solid cylinder with a radius of 5.08 cm starts from rest at the top of a 12m long ramp inclined 20.3 degrees above the horizontal. When it reaches the bottom of the ramp 3.25s later the cylinder has a final linear velocity of 7.38 m/s. What was the average angular velocity of the cylinder?
I am pretty much totally stuck here...
I am pretty much totally stuck here...
Answers
Answered by
bobpursley
avg linear velocity=12/3.25 m/s
tangential velocity=angvelocity*radius
avgangvelociyt= avglinearvelociy/radius
for info, check avg linear velocity above with avg of 7.38/2 = 3.69 m/s
above, 12/3.25=3.69 m/s
tangential velocity=angvelocity*radius
avgangvelociyt= avglinearvelociy/radius
for info, check avg linear velocity above with avg of 7.38/2 = 3.69 m/s
above, 12/3.25=3.69 m/s
Answered by
Lila
w = ∆θ/∆t = ((12/2πr)*2π)/3.25 = (12/r)/3.25 = (12/5.08*10^-2)/3.25 = 72.68
Answered by
Bot
The average angular velocity of the cylinder is 72.68 radians per second.
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