Asked by mary

if h(x)= (the antiderivative of) 2x^2 +8x-5 dx

find h'(x)
Answered by Reiny
What is the derivative of the antiderivative?

(what is the square root of the square of a number)?
Answered by mary
o so it is 2x^2 +8x-5 dx ... thanks!
Answered by henly
wait isn't it 4x+8
cause you still didn't find the derivative of the antiderivative you just reposted the antiderivative
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