Asked by Kevin
Prove the following to be an identity
(cotx + cscx)*(1-cosx)=sin x
(cotx + cscx)*(1-cosx)=sin x
Answers
Answered by
Anonymous
(cos/sin + 1/sin)(1-cos)
=(cos/sin+1/sin)(1)+(cos/sin+1/sin)(-cos)
= cos/sin+1/sin-cos^2/sin-cos/sin
= (1/sin )(1-cos^2) but 1-cos^2=sin^2
so
sin^2/sin
= sin
=(cos/sin+1/sin)(1)+(cos/sin+1/sin)(-cos)
= cos/sin+1/sin-cos^2/sin-cos/sin
= (1/sin )(1-cos^2) but 1-cos^2=sin^2
so
sin^2/sin
= sin
Answered by
Kevin
sin isnt an identity to begin with
and i got sin^2 x + cos^2 x = 1
the ansswer says its what i got
and i got sin^2 x + cos^2 x = 1
the ansswer says its what i got
Answered by
Damon
The right hand side says sin x
You must make the left hand side come out sin x
That is what I did
Yes, I also used sin^2 + cos^2 = 1
in saying
1 - cos^2 = sin^2
You must make the left hand side come out sin x
That is what I did
Yes, I also used sin^2 + cos^2 = 1
in saying
1 - cos^2 = sin^2
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