Asked by Amy

A football player kicks a field goal, launchingthe ball at an angle of 48" above the horizontal. During the kick, the ball is in contact with the player's foot for 0.045 s, and the ball's acceleration is 290 m/sz. Vvhat is the range of the football?
Answered by Scott
search "horizontal range formula"

launch velocity is ... 0.045 * 290
Answered by Amy
Thank you!
Answered by Amy
(13.05*sin(48)*2)/9.8=1.97 Is this correct?
Answered by Amy
sorry 13.05^2
Answered by Scott
try this ... [13.05^2 * sin(48 * 2)] / 9.8
Answered by Amy
Got it, thank you very much.
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