Question

A football player kicks a field goal, launchingthe ball at an angle of 48" above the horizontal. During the kick, the ball is in contact with the player's foot for 0.045 s, and the ball's acceleration is 290 m/sz. Vvhat is the range of the football?
search "horizontal range formula"

launch velocity is ... 0.045 * 290
Thank you!
(13.05*sin(48)*2)/9.8=1.97 Is this correct?
sorry 13.05^2
try this ... [13.05^2 * sin(48 * 2)] / 9.8
Got it, thank you very much.

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