Question

A player kicks a football from the ground at an angle of 42 degrees above the horizontal with an initial speed of 23m/s.
a. How high will the ball rise?
b. How long will it be in the air?
c. What will be its range?

Answer 1

use the initial speed to find the vertical initial speed. Then at the top, it has zero vertical velocity

vfv^2 = viv^2-2*9.8*height
0=viv^2-2*9.8*h solve for h.

time in air?
twice the time it takes to go to the top.
vfv=0=viv*t-4.9t^2 solve for t, double it.

Answer 2

What is the range?

Answer 3

The range R=23^2*sin(2*42)/9.8=53.68m

Answer 4

^ means???

Answer 5

x^2 is a way to indicate "x to the second power" or x&sup2

Answer 6

MathMate posted these last May:

- Some math symbols (omit spaces shown):
° & d e g ;
π & p i ;
≥ & g e ;
≤ & l e ;
α & a l p h a ;
∫ & i n t ;
Σ & S i g m a ;
√ & r a d i c ;
² & s u p 2 ;
³ & s u p 3 ;

Answer 7

HAHAHA. MAGARAL KAYO