Asked by Tsunayoshi

A player kicks a football from the ground at an angle of 42 degrees above the horizontal with an initial speed of 23m/s.
a. How high will the ball rise?
b. How long will it be in the air?
c. What will be its range?
Answered by bobpursley
use the initial speed to find the vertical initial speed. Then at the top, it has zero vertical velocity

vfv^2 = viv^2-2*9.8*height
0=viv^2-2*9.8*h solve for h.

time in air?
twice the time it takes to go to the top.
vfv=0=viv*t-4.9t^2 solve for t, double it.
Answered by Tsunayoshi
What is the range?
Answered by leonard
The range R=23^2*sin(2*42)/9.8=53.68m
Answered by Tsunayoshi
^ means???
Answered by Writeacher
x^2 is a way to indicate "x to the second power" or x&sup2
Answered by Writeacher
MathMate posted these last May:

- Some math symbols (omit spaces shown):
° & d e g ;
π & p i ;
≥ & g e ;
≤ & l e ;
α & a l p h a ;
∫ & i n t ;
Σ & S i g m a ;
√ & r a d i c ;
² & s u p 2 ;
³ & s u p 3 ;
Answered by ULOL
HAHAHA. MAGARAL KAYO
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