Question

A diamond's index of refraction for red light, 656 nm is 2.410 while that for blue light, 434 nm, is 2.450. Suppose white light is incident on the diamond at 30 degrees. Find the angles of refraction for these two colors.
Use Snell's Law: n1sin(theta1)=n2sin(theta2)
Since white light is incident at 30degrees, theta1 = 30.

Calculate the angle of refraction for the blue and red lights separately. For each case, n1 should be the index of air while n2 is the index for the blue or red light of diamond.
thank yall
working out those question for me please help me.

Related Questions

The index of refraction for a diamond for red light of wavelength 655 nm is 2.35, while that for b... A diamond's index of refraction for red light, 656 nm, is 2.410, while that for blue light, 434 nm,... 1.A beam of light passes through the air and enters a diamond at an angle of incidence of 40 degrees... Index of refraction Material Speed of Light (m/s) Index of Refraction Air 300,000,000 1.00 Water...