Asked by jessica
the index of refraction of h2o is 1.33. find the angle of refraction of a beam of light in air hitting the h2o surface at an angle of 60 degrees n(air)=1.00
Answers
Answered by
bobpursley
Snell's Law:
Angles are measured to the normal, not surface.
SinThetaincident*nair=SinThetaRefracted*nwater
sin30*1=SinTheta*1.33
theta=arcsin .377=22 deg
Angles are measured to the normal, not surface.
SinThetaincident*nair=SinThetaRefracted*nwater
sin30*1=SinTheta*1.33
theta=arcsin .377=22 deg
Answered by
jessica
k so the answer would b 22 degrees????
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