Asked by Majiri
A jack has a lever arm of 45cm and pitch of 0.5cm. If it's efficiency is 30%,what force is required to lift a load W of mass 1200kg
Answers
Answered by
Damon
final force needed = [1200 *9.81 / 0.30](.5/45)
Answered by
Majiri
Can you please drop the formula. Quite confuse.
Answered by
Scott
the mechanical advantage is ... (2 π 45) / .5
the weight of the load is ... 1200 g
the efficiency means that the mechanical advantage is reduced
... by 70% in this case
force needed ... (1200 g) / (4 π * 45 * .30)
the weight of the load is ... 1200 g
the efficiency means that the mechanical advantage is reduced
... by 70% in this case
force needed ... (1200 g) / (4 π * 45 * .30)
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