Asked by bob
The area of a triangle is 45cm and the altitude is 5cm greater than the base. Find the length of the base.
Answers
Answered by
Reiny
base --- b
height = b+5
(1/2)(b)(b+5) = 45
b^2 + 5b = 90
b^2 + 5b - 90 = 0
b = (-5 ±√385)/2
= appr 7.311 or some negative
base = 7.311 , height = 12.311
check
area = (1/2)(7.311)(12.311) = 45.0028..
not bad, my answer is correct
height = b+5
(1/2)(b)(b+5) = 45
b^2 + 5b = 90
b^2 + 5b - 90 = 0
b = (-5 ±√385)/2
= appr 7.311 or some negative
base = 7.311 , height = 12.311
check
area = (1/2)(7.311)(12.311) = 45.0028..
not bad, my answer is correct
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