Asked by Grace
A man uses a lever jack to lift a 2.00 × 10^3 kg car to change a tire. Each stroke of the jack lifts the car a distance of 5.00 × 10^(-3) m. The vertical displacement of the handle is 0.75 m for each stroke. How much total force does he use with each stroke of the jack?
A. 3.0 x 10^5 N
B. 2.9 x 10^6 N
C. 131 N
D. 19,600 N
A. 3.0 x 10^5 N
B. 2.9 x 10^6 N
C. 131 N
D. 19,600 N
Answers
Answered by
Damon
weight = 2 * 10^3 * 9.81 = 19.62*10^3 N
mechanical advantage = .75/.005
= 150
(19.62/150)* 10^3 = 130.8 N
mechanical advantage = .75/.005
= 150
(19.62/150)* 10^3 = 130.8 N
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