Asked by Lily
ron and kathy are ticket-sellers at their class play, ron handling student tickets that sell for $3.00 each and kathy selling adult tickets for $6.50 each.
If their total income for 29 tickets was $125.50, how many did ron sell?
If their total income for 29 tickets was $125.50, how many did ron sell?
Answers
Answered by
s
if its elementary algebra don't you draw some columns and guess and test?
otherwise, these are the equations:
x(3.00) + y(6.50) = $125.50
x+y = 29 tickets
otherwise, these are the equations:
x(3.00) + y(6.50) = $125.50
x+y = 29 tickets
Answered by
DrBob222
Let R = # tickets sold by Ron.
and K = # tickets sold by Kathy.
=================================
R+K = 29
3R + 6.50K = 125.50
=======================
Two equations; two unknowns. Solve for R and K.
and K = # tickets sold by Kathy.
=================================
R+K = 29
3R + 6.50K = 125.50
=======================
Two equations; two unknowns. Solve for R and K.
Answered by
lisa
thank u guys!
Answered by
shon
5x-10=15
Answered by
Teri
-2+4(x-1)= -7-4x
Answered by
leslie
your mama
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