Question
Tom and Kathy together have 30 chocolates.Both of them lost 6 chocolates each,and the product of the number of chocolates now they have is 80.Find out how many chocolates do they have at the beginning.
Answers
t+k=30
(t-6)(k-6)=80
(t-6)((30-t)-6) = 80
(t-6)(24-t) = 80
24t-t^2-144+6t = 80
t^2 - 30t + 224 = 0
(t-14)(t-16) = 0
...
(t-6)(k-6)=80
(t-6)((30-t)-6) = 80
(t-6)(24-t) = 80
24t-t^2-144+6t = 80
t^2 - 30t + 224 = 0
(t-14)(t-16) = 0
...
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