Asked by Anonymous

A cashier has 26 bills consisting of three times as many ones as fives, one less ten than fives, and the rest twenties. If the value is $120, find how many of each she has.
Answered by Ms. Sue
Obviously, you don't want help on this problem. You received two good answers when you asked this earlier this evening.

Please do not insult our tutors by ignoring their responses.
Answered by Scott
s = ones , f = fives , t = tens , w = twent

s + f + t + w = 26

s + 5f + 10t + 20w = 120

s = 3f , t = f - 1

the total value is divisible by 5, so the number of ones must be also
... the number of ones must also be divisible by 3
Answered by Scott
didn't see earlier answers, otherwise i would not have responded
Answered by Anonymous
Thank you all very much for your help. it's much appreciated.
Answered by Susa
X=FIVES
3X=ONES
X-1=TENS
27-5X=TWENTIES (26-(5X-1))
5X+3x+10(x-1)+20(27-5x)=120
Answered by Anonymous
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