Asked by Romanus
An object floats in a liquid of density 1.2 kg/m3 with one quarter of its volume above the liquid surface. Determine the density of the object
Answers
Answered by
Henry
Vb = Do/Dl * Vo.
3/4 = Do/1.2 * 1.
4Do = 3.6,
Do = 0.9kg/m^3. = Density of the object.
3/4 = Do/1.2 * 1.
4Do = 3.6,
Do = 0.9kg/m^3. = Density of the object.
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