Asked by ayesha

An object floats on water with 84% of its volume below the surface. The same object when placed in another liquid floats on that liquid with 74% of its volume below the surface. Determine the density of the unknown fluid
Answered by Henry
Do/Dw = 0.84
Do/1 = 0.84
Do = 0.84 g/cm^3 = Density of the object

Do/Df = 0.74
0.84/Df = 0.74
0.74Df = 0.84
Df = 1.135 g/cm^3 = Density of the fluid.
Answered by uday
v * density of object * g = .84v *1(density of water) *g
density of object = .84
v*density of object(.84) * g = .74v * density of unknown liquid * g
= density of unknown liquid is .84/.74
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