Asked by Idali
A 48-N object floats in a pool. If 75% of the volume of the object is immersed in the water, which statement is true about the buoyant force FB on the object?
A. FB=48N
B. FB=36N
C. FB=64N
D. FB=12N
E. This is not possible to answer with the information given.
A. FB=48N
B. FB=36N
C. FB=64N
D. FB=12N
E. This is not possible to answer with the information given.
Answers
Answered by
Henry
Do/Dw = 0.75.
Do/1 = 0.75, Do = 0.75g/cm^3 = Density of the object.
M*g = 48 N. M = 48/g = 48/9.8 = 4.90 kg. = 4900g = Wt. of object.
Vo = 4900g/(0.75g/cm^3) = 6533.3 cm^3 = Vol. of object.
0.75 * 6533.3 = 4900 cm^3 immersed = Vol. of water displaced.
4900cm^3 * 1g/cm^3 = 4900g = 4.9kg of water displaced.
Fb = M*g = 4.9 * 9.8 = 48 N.
Do/1 = 0.75, Do = 0.75g/cm^3 = Density of the object.
M*g = 48 N. M = 48/g = 48/9.8 = 4.90 kg. = 4900g = Wt. of object.
Vo = 4900g/(0.75g/cm^3) = 6533.3 cm^3 = Vol. of object.
0.75 * 6533.3 = 4900 cm^3 immersed = Vol. of water displaced.
4900cm^3 * 1g/cm^3 = 4900g = 4.9kg of water displaced.
Fb = M*g = 4.9 * 9.8 = 48 N.
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