Question

A stone is dropped from a height of 45 meter . what will be the distance travelled by it during the last second of its motion ? take acceleration as g=9.8m/s^2

Answer 1

How long does it take to hit?

h(t) = 45-4.9t^2
when is h=0?
t = 3.03 seconds

Now, what is h(2.03)?

Answer 2

If g =10 then Ans is 25 m distance travelled in last second ..Now how to solve it we use formula h=1/2 gt^2,Hn =g(n-1/2)