Asked by Mocha
A stone is dropped from a height of 49m and simultaneously another stone is thrown upwards from the ground with a speed of 40m/s.when and where do the two stones meet?
Answers
Answered by
bobpursley
falling stone: hf=49-4.9t^2
rising stone: hf=0+40t-4.9t^2
set the equations equal (hf=hf), and solve for time t, then put that t into either of the original equations and solve for hf.
rising stone: hf=0+40t-4.9t^2
set the equations equal (hf=hf), and solve for time t, then put that t into either of the original equations and solve for hf.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.