Asked by mora
A stone is dropped from a height 80m calculate k.e and p.e at ts t 2 s
Answers
Answered by
Tom
distance = 1/2 at^
a= 9.8 m/s/s. and t=2s
plug in and find the distance it has dropped.
subtract that distance from 80m to find the new height. PE = mgh, where h is the height.
Plug in and find PE
KE = 1/2 mv^2, so we need v after 2s
The equation is v= vo + at, and vo=0
So, v = 9.8(2). Multiply and find v
Plug v into the KE equation
a= 9.8 m/s/s. and t=2s
plug in and find the distance it has dropped.
subtract that distance from 80m to find the new height. PE = mgh, where h is the height.
Plug in and find PE
KE = 1/2 mv^2, so we need v after 2s
The equation is v= vo + at, and vo=0
So, v = 9.8(2). Multiply and find v
Plug v into the KE equation
Answered by
Bob
This question can not be answered as you need to know the mass (or weight, since we're on earth) of the stone:
PE = mass x height x acceleration
KE = mass x velocity^2 / 2
PE = mass x height x acceleration
KE = mass x velocity^2 / 2
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