Asked by GAurav
A Stone of 5 kg falls from the top of a cliff 50 m high and buries 1m in sand. Find the average resistance offered by the way sand and the time taken to penetrate.
Answers
Answered by
bobpursley
force*distance=energyfromfalling= mgh
force=5*9.8*50/5 N
force=5*9.8*50/5 N
Answered by
bobpursley
time:
force*time= mass*changeinvelocity
change in velocity:
1/2 m vf^2=mgh
vf=sqrt(2gh)
time= mass*sqrt(2gh)/forceabove
force*time= mass*changeinvelocity
change in velocity:
1/2 m vf^2=mgh
vf=sqrt(2gh)
time= mass*sqrt(2gh)/forceabove
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