Asked by -Untamed-
A stone falls freely from rest for 8.0s.
A. Calculate the stone's velocity after 8.0s.
V2-V1+at
V2 = (0) = 9.8(8.0)
V2 = 78.4m/s
B. What is the stone's displacement during this time?
d = (v2 + v1)t/2
d = (78.4 + 0)/2(8.0)
d = 313.6m
A. Calculate the stone's velocity after 8.0s.
V2-V1+at
V2 = (0) = 9.8(8.0)
V2 = 78.4m/s
B. What is the stone's displacement during this time?
d = (v2 + v1)t/2
d = (78.4 + 0)/2(8.0)
d = 313.6m
Answers
Answered by
drwls
You seem to be mixing up your = and - signs in the first two equations. Those were probably just typing errors.
I agree with your answers.
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