Asked by Rose
A 6.0 kg mass is pulled horizontally along a level surface where the coefficient of friction is
0.20. The mass accelerates at 0.68 m/s2.
a) What is the friction force acting on the mass?
b) What applied force is being used to pull the mass?
0.20. The mass accelerates at 0.68 m/s2.
a) What is the friction force acting on the mass?
b) What applied force is being used to pull the mass?
Answers
Answered by
Henry
M*g = 6 * 9.8 = 58.8 N. = Wt. of Mass. = Normal force(Fn).
a. Fk = u*Fn = 0.20 * 58.8 = 11.8 N. - Force of kinetic friction.
b. Fap-Fk = M*a.
Fap = ?.
a. Fk = u*Fn = 0.20 * 58.8 = 11.8 N. - Force of kinetic friction.
b. Fap-Fk = M*a.
Fap = ?.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.