Asked by kem
A block of 25 is pulled horizontally on a rough surface by the force 120N.the coefficient of friction between the surface is 0.34 how do i calculate the accelation of the block
Answers
Answered by
Henry
M*g = 25kg * 9.8N/kg = 245 N. = Wt. of block. = Normal(Fn).
Fap = 120 N. = Force applied.
Fk = u*Fn = 0.34 * 245 = 83.3 N.
a = (Fap-Fk)/M m/s^2.
Fap = 120 N. = Force applied.
Fk = u*Fn = 0.34 * 245 = 83.3 N.
a = (Fap-Fk)/M m/s^2.