Question
A 5 kg block rests on a horizontal surface. Determine the horizontal force required to accelerate the block at 3 m/s^2. The frictional coefficient is 0.5.
Fnet=mass(accer.)
FH=5kg (3m/s^2)= 15N
I don't know what to make of the frictional coefficient
Fnet=mass(accer.)
FH=5kg (3m/s^2)= 15N
I don't know what to make of the frictional coefficient
Answers
Henry
m*g = 5kg * 9.8N./kg = 49 N.
Fk = u*mg = 0.5 * 49 = 24.5 N. = Force of kinetic friction.
Fx-Fk = m*a
Fx-24.5 = 5 * 3 = 15
Fx = 15 + 24.5 = 39.5 N.
Fk = u*mg = 0.5 * 49 = 24.5 N. = Force of kinetic friction.
Fx-Fk = m*a
Fx-24.5 = 5 * 3 = 15
Fx = 15 + 24.5 = 39.5 N.