Asked by Tristan
A 5 kg block rests on a horizontal surface. Determine the horizontal force required to accelerate the block at 3 m/s^2. The frictional coefficient is 0.5.
Fnet=mass(accer.)
FH=5kg (3m/s^2)= 15N
I don't know what to make of the frictional coefficient
Fnet=mass(accer.)
FH=5kg (3m/s^2)= 15N
I don't know what to make of the frictional coefficient
Answers
Answered by
Henry
m*g = 5kg * 9.8N./kg = 49 N.
Fk = u*mg = 0.5 * 49 = 24.5 N. = Force of kinetic friction.
Fx-Fk = m*a
Fx-24.5 = 5 * 3 = 15
Fx = 15 + 24.5 = 39.5 N.
Fk = u*mg = 0.5 * 49 = 24.5 N. = Force of kinetic friction.
Fx-Fk = m*a
Fx-24.5 = 5 * 3 = 15
Fx = 15 + 24.5 = 39.5 N.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.