Asked by Pat
A 6.0 kg block of ice rests on a surface that is tilted by = 12°. Find the acceleration of the block ignoring any friction.
Answers
Answered by
bobpursley
weight down the plane: mgsinTheta
force down the plane=ma
mgsinTheta=ma
solve for acceleration a.
force down the plane=ma
mgsinTheta=ma
solve for acceleration a.
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