Asked by mary
A baseball is thrown, leaving the baseball player’s hand 6.0 ft about the ground and at a 45 degree angle with respect to the horizon. The initial speed is 80 ft/s. Find the maximum height attained, the length of time the ball stays in the air, and the horizontal distance where the ball hits the ground. (assume air resistance is negligible).
Answers
Answered by
bobpursley
YOu know the initial vertical component, and the initial horizontal component.
final height=initialheight+vovertical*time-1/2 g time^2
solve for time...this is time in the air.
Now at max height, vvertical will be zero
0=vovertical-g*time solve for time max height, then use that time in the h equation to determine height.
final height=initialheight+vovertical*time-1/2 g time^2
solve for time...this is time in the air.
Now at max height, vvertical will be zero
0=vovertical-g*time solve for time max height, then use that time in the h equation to determine height.
Answered by
msdh
0.7
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