You need to make an aqueous solution of 0.233 M magnesium nitrate for an experiment in lab, using a 125 mL volumetric flask. How much solid magnesium nitrate should you add? (fill in blank)

Question

__ grams

Answer 1

See your former post and work backwards to that.
How many mols do you need of Mg(NO3)2?
That's mols = M x L = ?
Then mols = grams/molar mass. Solve for grams Mg(NO3)2.
Post your work if you get stuck.