Question

A galvanometer of resistance 50 ohm which gives a full deflection for 1mA is to be adapted to measure currents up to 5A. Calculate the resistance of the resistor required
5A = 5,000mA.
Ig = 1mA. = Current through the galvanometer.
Ir = 4,999mA = Current through the resistor.

R = (1mA/4,999mA) * 50 Ohms = 0.01 Ohms in parallel with the galvanometer.

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