Add a resistor in series with the
coil:
R+12 = E/I = 10/0.0025 = 4,000,
R = 4,000-12 = 3,988 Ohms.
A GALVANOMETER WITH COIL RESISTANCE 12.0OHMS SHOWS FULL SCALE DEFLECTION FOR A CURRENT OF 2.5MA HOW WOULD YOU CONVERT IT INTO A VOLTMETER OF RANGE 0 TO 10VOLTS
2 answers
R = (10-0.0025*12)/0.0025 = 9.97/0.0025 = 3,988 Ohms.