Asked by un
A ball is thrown vertically upwards with a velocity of 2 m/s. It is seen at height h twice.
Find the sum of the times, measured in seconds from the moment the ball is thrown, at which it is seen at height h.
Take g=10m/s²
Neglect air resistance.
Find the sum of the times, measured in seconds from the moment the ball is thrown, at which it is seen at height h.
Take g=10m/s²
Neglect air resistance.
Answers
Answered by
MathMate
Hints:
The average of the times is equal to the time to reach the maximum height, due the the symmetry of the parabola.
So the sum of the times would be twice the time it takes to reach the maximum height, also equal to the time for the object to go up and fall back to the original elevation. So figure out whichever is easier for you.
The average of the times is equal to the time to reach the maximum height, due the the symmetry of the parabola.
So the sum of the times would be twice the time it takes to reach the maximum height, also equal to the time for the object to go up and fall back to the original elevation. So figure out whichever is easier for you.
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