v(t)=vi-9.8t
d(t)=+vi*t-4.9t^2
A ball is thrown vertically upward from the ground with a speed of 36.0 m/s.Suppose the acceleration of gravity were only 2.00 m/s^2 instead of 9.80 m/s^2
a)At what time does it have a velocity of 12.0 m/s upward?
b)At what time does it have a velocity of 12.0 m/s downward?
c)When is the velocity of the ball zero?
d)When is the displacement of the ball zero?
e)What are the magnitude and direction of the acceleration while the ball is moving upward?
f)What are the magnitude and direction of the acceleration while the ball is moving downward?
g)What are the magnitude and direction of the acceleration when it is at highest point?
1 answer
1 answer