Question

A ball is thrown vertically upward with an initial velocity of 135 feet per second, the ball’s height after t second is s(t) = 135t – 22t
How to calculate average velocity from 1 to 3 seconds?
According to my knowledge of physics,

s(t) = 135t - 16t^2

Anyway, average velocity = total.distance/total.time
So, that would be (s(3)-s(1))/(3-1)

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