Asked by Jhon Paulo
A ball is thrown vertically upward from the ground with an initial velocity of sixty four feet per second. if the positive direction is up to 't' seconds is the time the has elapse since the ball was thrown and 's' is the distance of the ball from the starting point at 't' seconds. Then, the equation is s is equal to negative sixteen plus sixty four t.
Find the instantaneous velocity of the ball when it reaches the ground.
Find the instantaneous velocity of the ball when it reaches the ground.
Answers
Answered by
Damon
no
s = -16 t^2 + 64 t
If the ball left the ground with velocity + 64 ft/x then it returns to earth with velocity -64 ft/s.
Your parabola is symmetrical and the vertex is at the top,
s = -16 t^2 + 64 t
If the ball left the ground with velocity + 64 ft/x then it returns to earth with velocity -64 ft/s.
Your parabola is symmetrical and the vertex is at the top,
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