Asked by fred
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2
What is the velocity of the ball when it is 96 ft above the ground on its way up?
What is the velocity of the ball when it is 96 ft above the ground on its way up?
Answers
Answered by
drwls
Solve the equation
16t^2 -160t +96 = 0
There will be two roots. Take the lowest t value as the solution. That will be the answer when the ball is going up.
Note that the equation can be simplifed to
t^2 -10t + 16 = 0
which factors easily.
16t^2 -160t +96 = 0
There will be two roots. Take the lowest t value as the solution. That will be the answer when the ball is going up.
Note that the equation can be simplifed to
t^2 -10t + 16 = 0
which factors easily.
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