Asked by Adam

Juan throws a baseball with an initial speed of 40 m/s at an angle of 56 0 above the horizontal. Richard catches the ball at the same height that Juan threw it. How far did Juan throw the ball?

Answers

Answered by Scott
the basic range equation is

d = v^2 * sin(2Θ) / g

v = launch velocity
Θ = launch angle
g = gravitational acceleration

level surface (same height)
no air resistance
Answered by Adam
Scott you're a legend among men.

anyone who reads this, be sure you double angle theta in sine, it took me a second to figure that out, but no worries Scott thank you so much!!!!

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