Asked by Adam
Juan throws a baseball with an initial speed of 40 m/s at an angle of 56 0 above the horizontal. Richard catches the ball at the same height that Juan threw it. How far did Juan throw the ball?
Answers
Answered by
Scott
the basic range equation is
d = v^2 * sin(2Θ) / g
v = launch velocity
Θ = launch angle
g = gravitational acceleration
level surface (same height)
no air resistance
d = v^2 * sin(2Θ) / g
v = launch velocity
Θ = launch angle
g = gravitational acceleration
level surface (same height)
no air resistance
Answered by
Adam
Scott you're a legend among men.
anyone who reads this, be sure you double angle theta in sine, it took me a second to figure that out, but no worries Scott thank you so much!!!!
anyone who reads this, be sure you double angle theta in sine, it took me a second to figure that out, but no worries Scott thank you so much!!!!