Question

A student throws a baseball vertically upward, and 2.8s later catches it at the same level. Neglecting air resistance , calculate the following

(a) the velocity at which the ball left the students hand

(b) the height to which the ball climbed above the students hand

Answer 1

(a) The baseball reached maximum height and zero velocity after t = 1.4 seconds, half the total interval. The initial velocity was Vo = g*t = 13.72 m/s

(b) The height reached is
H = (1/2) Vo t = Vo^2/(2g)