Asked by Jared

Keisha throws a baseball with an initial velocity of 30 m/s at 30.0° above the horizontal. If air resistance is negligible, how long does it take for the baseball to reach the maximum height of its trajectory?

Assume that the acceleration due to gravity is given by: g = 10 m/s^2
sin(30.0°) = 1/2
cos(30.0°) = √(3) / 2
Answered by Steve
v = 30*sin30° - 9.8t

it reaches max height when v=0.
Answered by Anonymous
1.5s