q = mc(Tfinal-Tinitial)
1800 =40*0.903(Tf=25)
Find the final temperature, given that the initial temperature of a 40 g piece of Aluminum is 25 degrees Celsius and it is heated with 1800 J of heat. The specific heat capacity of Aluminum is 0.903
3 answers
Am I supposed to multiply everything on the right side then divide it by 1800?
You're stuck with the math.
You clear the parentheses first.
1800 = 40*0.903*Tf - 40*0.903*25
Now combine terms, then
Solve for Tf, the only unknown in the equation. That's the final T.
You clear the parentheses first.
1800 = 40*0.903*Tf - 40*0.903*25
Now combine terms, then
Solve for Tf, the only unknown in the equation. That's the final T.
3 answers