Asked by Chironjit

What is the final temperature (degrees celcius) of 1.36g of water with an initial temperature of 23.0degrees celcius after 6.420J of heat is added to it?
Answered by Anonymous
m=dv
mol C2H2=m/molar mass
heat(q)= (delta H)(mol)
Answered by DrBob222
q = [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
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