Asked by Kayla

A 1200Kg car travels at a constant speed of 26m/s for 5s up a 130m long hill. The total height of the hill is 27m & the friction force acting on the car is 2520N.
What power was used by the car in traveling up the hill?

I know that Fnet=o bc velocity is constant, therefore Fapp=2520N

I used (Fapp * d)/t so (2520 * 130)/5 to get 6.55 * 10^4

I got it incorrect... Am I supposed to do something with the height distance as well?

Thanks a bunch! :D

Answers

Answered by Scott
work against friction is
... 2520 N * 130 m

change in gravitational potential is
... m g h = 1200 kg * g * 27 m

the sum is the total energy

energy divided by time (5 s) is the power
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions