Asked by Lammii
A car of m=1200kg accelerates 5m/s to 15m/s.force=6000N.what distance did the forces act?
Answers
Answered by
Anonymous
Plug and chug
a = F/m = 6000 / 1200 = 5 m/s^2
v = Vi + a t
15 = 5 + 5 t
10 = 5 t
t = 2 seconds
d = Vi t + (1/2) a t^2
d = 5 (2) + (5/2)(4) = 10 + 10 = 20 meters
a = F/m = 6000 / 1200 = 5 m/s^2
v = Vi + a t
15 = 5 + 5 t
10 = 5 t
t = 2 seconds
d = Vi t + (1/2) a t^2
d = 5 (2) + (5/2)(4) = 10 + 10 = 20 meters
Answered by
Seble wongel
W=∆KE
Fs=1/2mv^2-1/2mu^2
s=20m
Fs=1/2mv^2-1/2mu^2
s=20m
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