Asked by Jaslyn
Would the limit of lim x-->3 (x^3 -27)/(x^2 -9) be:
9/2?
9/2?
Answers
Answered by
drwls
The numerator and denominator of the fraction can be factored and common (x-3) factors canceled to give
(x^2 + 3x +9)/(x+3)
When x = 3, that fraction is 27/6 = 9/2
You can also use L'Hopital's rule to get the same answer.
Your answer is correct.
(x^2 + 3x +9)/(x+3)
When x = 3, that fraction is 27/6 = 9/2
You can also use L'Hopital's rule to get the same answer.
Your answer is correct.
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