Someone drops a ball from the roof of your building.The ball drop past your window. It takes time T to pass the window's height. What is the initial speed of the ball when it first came in view?
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V1 = speed at top of window
V2 = speed at bottom of window
h = height of window
T = time of passage
[(V1 + V2) / 2] * T = h
V2 = V1 + g T
[(V1 + V1 + g T) / 2] * T = h
V1 T + (g T^2 / 2) = h
V1 = (h / T) - (g T / 2)
V2 = speed at bottom of window
h = height of window
T = time of passage
[(V1 + V2) / 2] * T = h
V2 = V1 + g T
[(V1 + V1 + g T) / 2] * T = h
V1 T + (g T^2 / 2) = h
V1 = (h / T) - (g T / 2)
1 answer