Asked by Kathy

Lizette drops a ball from a height
of 256 feet. The peak height after each bounce is 75% the previous height. How
much vertical distance does the ball travel from the time she drops it until it touches the ground after its
fourth
bounce

Answers

Answered by Steve
256 + 2*256*.75 + ... + 2*256*.75^4
= 2*256(1-.75^5)/(1-.75) - 256
= 1306
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